Question
A 4 cm wire carrying a current of 15 A is placed inside
a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?Solution
i=15 A, l=4cm=0.04m, B=0.27T and θ=90 ∘ Magnetic force on a current carrying conductor is given by: →F=i(→l×→B)=ilBsinθ F=15×0.04×0.27×sin90 ∘ F=16.2×10−2N
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