The storage battery of a car has an emf of 15 V. If the internal resistance of the battery is 0.5 Ω, what is the maximum current that can be drawn from the battery?
In the above question it is given that: Emf of the battery, E= 15V Internal resistance of the battery, r = 0.5 Ω Consider the maximum current drawn from the battery to be I. Therefore, using Ohm’s law, E = Ir => I = E/r => I = 15/0.5 => I = 30 A Clearly, the maximum current drawn from the given battery is 30A
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