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Emf of the battery, E = 12V Internal resistance of the battery, r = 4 ohm Current = 0.6 A so, I = E/(R + r) R + r = E/I = 12/0.6 = 20 ohm Therefore = 20 - 4 = 16 ohm Terminal voltage of resistor = V so, V = IR => 0.6 x 16 => 9.6 V
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