Question
A rocket with a lift-off mass 10,000 kg is blasted
upwards with an initial acceleration of 5.0 m s–2. Calculate the initial thrust (force) of the blast.Solution
Given that Mass of the rocket, m = 10,000 kg Initial acceleration, a = 5 m/s2 Acceleration due to gravity, g = 10 m/s2 Using Newton’s second law of motion, the net force (thrust) acting on the rocket is equal to F - mg = ma F = m(g + a) F = 10000 × (10 + 5) N = 10000 × 15 N = 15 × 104 N
17.5% of 400 – 24% of 150 = ?
- Find the simplified value of the given expression.

(54/6) × 5 + 12 × (17/2) = ?% of 700
(2/5)(32% of 4500 – 440) = ? × 8
3/4 of 2000 + √1024 = ? + 12.5% of 3200
(92.03 + 117.98) ÷ 14.211 = 89.9 – 30.23% of ?
8 × 9 + ? – 6 × 11 = 12 × 8
128 ÷ 22 × ? = 15% of 300 ÷ 9
Find the Value of √(-√3+√(3+8√(7+4√3)))?Â
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is: