Question
Specific heat of aluminum when 26000 J of energy is
supplied to 4 kg block and it's temperature rises from 25°C to 35°C isSolution
Given that, Q = 26000 J, m = 4 kg ΔT = 35 - 25 = 10 K we know that, specific heat is given by Q = mCΔt ⇒ 26000 = 4 × C × 10 ⇒ C = 650 J/kg-K
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