New Enroll for RBI, PFRDA & NABARD Intro Class! April 18 at 9:15 PM

    Question

    A current-carrying conductor is placed perpendicular to

    a uniform magnetic field. The force on the conductor is given by:
    A F=B I L Correct Answer Incorrect Answer
    B F=B I Lsinθ Correct Answer Incorrect Answer
    C F=B I Lcosθ Correct Answer Incorrect Answer
    D F= B2 I L Correct Answer Incorrect Answer

    Solution

    The force on a current-carrying conductor in a magnetic field is given by: F=BILsinθ For a conductor placed perpendicular to the field, θ=90∘, so sin 90° = 1, and F=BIL.

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