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Borrowing 2 bits from the host portion of the IP address increases the number of subnet bits from 24 to 26 (since the original mask is /24). With 2 bits for subnets, 22=42^2 = 422=4 subnets can be created. The new subnet mask will be 255.255.255.192 (or /26), which leaves 6 bits for the host portion, allowing 64 addresses per subnet (with 62 usable addresses). Why Other Options are Incorrect: A) 2 subnets, 255.255.255.128: Borrowing only 1 bit from the host portion would create 2 subnets, but the question specifies borrowing 2 bits. C) 6 subnets, 255.255.255.224: This option provides an incorrect number of subnets based on the number of bits borrowed. D) 8 subnets, 255.255.255.240: Borrowing 3 bits would yield 8 subnets, not 4. E) 16 subnets, 255.255.255.248: Borrowing 4 bits would create 16 subnets, which is beyond the scope of this question.
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. x³= ((4)5+ (15)³)/(3)4
II. 8y³=(-13)3÷ √1521+ (3y)³
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
I. x2 - 11x + 24 = 0
II. y² - 5y + 6 = 0
What will be the product of smaller roots of both equations.
I. 8x – 3y = 85
II. 4x – 5y = 67
If x2 - 3x - 18 = 0 and y2 + 9y + 18 = 0, which of the following is true?
I. 10x² - 11x + 3 = 0
II. 42y² - 23y – 10 = 0
