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The fundamental feature of an RDBMS is its organization of data into tables. These tables are structured in rows (tuples) and columns (attributes), forming a relational model. 1. Tabular Structure: Each table in an RDBMS has a unique name and predefined columns, where rows contain individual records. This logical structure makes data easy to query and manipulate. 2. Relational Integrity: Relationships between tables are established using keys such as primary keys and foreign keys. 3. Query Language: SQL is employed for querying, updating, and managing the data efficiently. 4. Advantages: Data consistency, integrity, and flexibility in querying make RDBMS a preferred choice for structured data applications. This tabular format is what differentiates relational databases from other models, enabling structured, predictable, and optimized data access. Why Other Options Are Incorrect: • A) Stores data in hierarchical structures: This describes hierarchical databases, not RDBMS. Hierarchical databases organize data in a tree-like structure. • B) Uses fixed-length files for data storage: While file-based systems may use fixed-length records, RDBMS offers dynamic storage. • D) Data is stored as key-value pairs: Key-value pair storage is a characteristic of NoSQL databases, not RDBMS. • E) Supports only unstructured data formats: RDBMS focuses on structured data stored in a well-defined schema, unlike systems designed for unstructured data (e.g., document databases).
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I.8(x+3)+ 8(-x)=72
II. 5(y+5)+ 5(-x)=150
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I: 3x² - 18x + 24 = 0
II: 5y² + 10y - 15 = 0