5,1,4,2,8 how many more pass are needed to finish

Solution

First Pass: (5 1 4 2 8 ) –> (1 5 4 2 8 ), Here, algorithm compares the first two elements, and swaps since 5 > 1. ( 15 4 2 8 ) –> ( 14 5 2 8 ), Swap since 5 > 4 ( 1 45 2 8 ) –> ( 1 42 5 8 ), Swap since 5 > 2 ( 1 4 25 8 ) –> ( 1 4 25 8 ), Now, since these elements are already in order (8 > 5), algorithm does not swap them. Second Pass: (1 4 2 5 8 ) –> (1 4 2 5 8 ) ( 14 2 5 8 ) –> ( 12 4 5 8 ), Swap since 4 > 2 ( 1 24 5 8 ) –> ( 1 24 5 8 ) ( 1 2 45 8 ) –> ( 1 2 45 8 ) Now, the array is already sorted, but our algorithm does not know if it is completed. The algorithm needs onewhole pass withoutany swap to know it is sorted. Third Pass: (1 2 4 5 8 ) –> (1 2 4 5 8 ) ( 12 4 5 8 ) –> ( 12 4 5 8 ) ( 1 24 5 8 ) –> ( 1 24 5 8 ) ( 1 2 45 8 ) –> ( 1 2 45 8 )