AB ->C satisfies condition1 (all the values of AB are unique), but C->B does not satisfy any of the three conditions (C has not unique values, B has not all same values and the value of C is repeated two times (8, 5) then the value of B is not repeated), so option 1 is incorrect. B->C A satisfies condition1, and B-> C also satisfies condition1, so option 2 is correct. B->C A satisfies condition1, but A->C does not satisfy any of the three conditions, so option 3 is incorrect. A->C B does not satisfy any of the three conditions, and B-> C satisfies condition1, so option 4 is incorrect. Since BC ->A && B ->C holds in above relation, option 2 will be the answer.
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