Start learning 50% faster. Sign in now
Section 65 of Evidence Act: Cases in which secondary evidence relating to documents may be given––Secondary evidence may be given of the existence, condition or contents of a document in the following cases:– (a) when the original is shown or appears to be in the possession or power–– of the person against whom the document is sought to be proved, or of any person out of reach of, or not subject to, the process of the Court, or any person legally bound to produce it, and when, after the notice mentioned in section 66, such person does not produce it; (b) when the existence, condition or contents of the original have been proved to be admitted in writing by the person against whom it is proved or by his representative in interest; (c) when the original has been destroyed or lost, or when the party offering evidence of its contents cannot, for any other reason not arising from his own default or neglect, produce it in reasonable time; (d) when the original is of such a nature as not to be easily movable; (e) when the original is a public document within the meaning of section 74; (f) when the original is a document of which a certified copy is permitted by this Act, or by any other law in force in India to be given in evidence (g) when the originals consist of numerous accounts or other documents which cannot conveniently be examined in Court, and the fact to be proved is the general result of the whole collection.
The HCF and LCM of 2 numbers are 2 and 60 respectively. If one of the numbers is 14 more than the other, find the smaller number.
Let N be the greatest number that will divide 86, 120, 154 leaving the same remainder in each case. Then sum of the digits in N is:
The LCM of the two numbers is 12 times their HCF. The sum of LCM and HCF is 429 and if both the number are smaller than their LCM. Find both numbers.
Let x be the smallest number which when subtracted from 31560 makes the resulting number divisible by 13, 16, 25 and 30. The product of the digits of x ...
The least number which when divided by 10, 12, 15 and 20 leave zero remainder in each case and when divided by 24 leaves a remainder of 12 is:
The LCM of x and y is 2057 and their HCF is 23. If x = 187, what will be the value of y?
Find the greatest number which when divide 80,121 & 148 leave remainder 2, 4 & 5 respectively?
Let N be the greatest number that will divide 82, 105, 128 leaving the same remainder in each case. Then sum of the digits in N is: