Question
Under Section 320(1) of Cr.PC for fraudulent removal or
concealment of property etc. to prevent distribution among creditors, which section of IPC is applicable?Solution
Section 421, IPC. Dishonest or fraudulent removal or concealment of property to prevent distribution among creditors.—Whoever dishonestly or fraudulently removes, conceals or delivers to any person, or transfer or causes to be transferred to any person, without adequate consideration, any property, intending thereby to preÂvent, or knowing it to be likely that he will thereby prevent, the distribution of that property according to law among his creditors or the creditors of any other person, shall be punished with imprisonment of either description for a term which may extend to two years, or with fine, or with both CLASSIFICATION OF OFFENCE Punishment—Imprisonment for 2 years, or fine, or both—Non-cognizÂable—Bailable—Triable by any Magistrate—Compoundable by the crediÂtor who are affected thereby with the permission of the court.
The LCM of two numbers is 432 and their HCF is 55. If one of the numbers is 132, the other number is:
What will be the greatest common divisor (GCD) of (x² - 8x + 15) and (x² - 11x + 30).
The product of two positive integers is 1620. If their HCF is 9 and their sum is 81, then find the difference between the numbers.
Sum of the two numbers is 32 and their HCF and LCM are 4 and 60, respectively. Find the sum of reciprocal of the given two numbers.
Let N be the greatest number that will divide 82, 105, 128 leaving the same remainder in each case. Then sum of the digits in N is:
The product of two numbers is 4,320 and their highest common factor is 24. Find the least common multiple of these two numbers.
Let N be the greatest number that will divide 89, 110, 131 leaving the same remainder in each case. Then sum of the digits in N is:
LCM and HCF of two numbers are respectively 3 and 18. If one of them is 9, find the other number.
Find the smallest number that leaves 16 as remainder when divided by both 28 and 42.
The greatest number of four digits which when divided by 10, 12, 14 leave remainders 8, 10, 12 respectively is:
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