Two boys are on opposite sides of a tower of 100 m height. If they measure the elevation of the top of the tower as 30° and 45° respectively then the distance between the boys is?
Let AB is tower of 100m height x,y are the place where 2 boys standing. ∠AxB = 30° ∠AyB = 45° D = h (cotα + cotβ) D = 100 (cot30° + cot45°) D = 100 (√3 + 1) Then distance between the boys is = 100 (√3 + 1)
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