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Let, unit’s digit and ten’s digit of number be 2x and 3x respectively. 2x + 3x = 15 5x = 15 x = 15/5 = 3 Therefore, required number = 96 So, products of digits = 9 × 6 = 54
Find the missing character.
9 25 ? 121 221 337
...64, 79, 109, 169, 289, ?
13 19 32 52 ? 113
8 27 64 125 ? 343
...60, 100, 160, 240, ?, 460
What value should come in the place of (?) in the following number series?
192, 96, 96, 144, ?, 720
11 16 42 141 ? 2945 17700
...