Question
In a mixture 'P', 5 liters of
water are replaced with honey, resulting in the mixture containing 55% honey. If the original mixture 'P' consisted of 50% water, determine the volume of honey in the original mixture.Solution
ATQ,
Original mixture has 50% water and 50% water. Let the total volume of the original mixture be x. According to the question, 0.5x + 5L = 55% of x = 0.55x 0.05x = 5 x = 100 L Volume of honey in the original mixture = 50% of x = 0.5 × 100 = 50 L
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