Let Adam’s age = x Peter’s age = (x-7) 20 years hence, Adam’s age = (x+ 20) years 5 years ago, Peter’s age = x-7- 5 = (x- 12) years Now, (x+20) = 3 (x-12) x+ 20= 3x - 36 2x = 56 x= 56/2 = 28 years Hence, Adam = 28 years Peter = 28 - 7 = 21 years Sum of the present ages of Adam and Peter = 28 + 21 = 49 years
Determine the probability that when a hand of 7 cards is drawn from a box of 52 cards, it consists at least 3 kings?
In a bag, there are three different colour balls namely red, yellow and white. The sum of the number of yellow and red balls in the bag is equal to the ...
In a lottery, there are 11 prizes and 22 blanks. A lottery is drawn at random. What is the probability of getting a prize?
...From a bag containing 12 white and 15 yellow ribbons, find the probability of picking 2 ribbons of each type at random.
Five squares of a chessboard are chosen at random, the probability that three are of one colour and two of another is
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A jar contains 54 marbles each of which is blue green or white. The probability of selecting a blue marble at random from the jar is 1/3 and the probabi...
If the letters of the word PARAM are arranged at random, what is the probability that all vowels will come together?
Given that E and F are events such that P(E) = 0.7, P(F) = 0.4 and P(E ∩ F) = 0.3, find P(E|F) and P(F|E)