Question
The ratio of the present age of A to that of B is 7:9.
Six years ago the ratio of 1/3 of A’s age at that time and 1/3 of B’s age at that time was 1:3. What will be the ratio of A’s age to B’s age 5 years from now?Solution
Let the present age of A and B be 7x and 9x respectively. Now, (1/3(7x-6))/(1/3(9x-6))= 1/3 So ((7x-6))/((9x-6)) = 1/3 ⇒ 21x – 18 = 9x – 6 ⇒ 12x = 12  ∴ x = 1 ∴ 5 years from now, A’s age = 7x + 5 = 7 + 5 = 12 years B’s age = 9x + 5 = 14 years ∴ Required ratio = 12/14 = 6:7
(2099.92 ÷ 25.02 of ? × 199.56 + 1199.95) = 3999.86
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? = 540.24 + 1022.97 – 11.992 Â
139.88% of 145.09 + 721.93 ÷ 38.13 +? = 29.14 * 8.18
1299.999 ÷ 325.018 × 24.996 = ?
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9
(13.156)2 + (3.945)2 + (5.903)3 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
20.99 × √4.09 × 30.09 = ? × √195.99 × 15.09