The present age of A is 5/2 times to that of his marriage age. Present age of his brother is 1/5th of his present age. If A was married 36 years ago then find the present age of his brother.
Let the age of A when he was married be x years. Present age of A = 5x/2 Present age of his brother = (1/5) × (5x/2) = x/2 According to Question, => x + 36 = 5/2x => 3/2x = 36 => x = 24 years Present age of his brother = (1/2) × 24 = 12 years
120.02% of 599.90 + (34.78/20.89) × (47.98) = ?2 – 10.022
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? = (5.8)2 + (8.9)2 + (4.7) 2 + 24.7% of 20
(5.013 – 20.04) = ? + 9.98% of 6199.98
?% of (144.31 ÷ 17.97 × 60.011) = 239.98
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
45.22% of (71.9 x 5.01) + 69.97 =?
? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03
?% of 549.83 – 18.05 × 31.96 = 44.94% of 479.84 – 13.98 × 33.13
