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    Question

    A is five times as old as B. C was twice-as old as A six

    years ago. In six years' time, A will be 31. Find the sum of the present ages of B and C.
    A 31 Correct Answer Incorrect Answer
    B 49 Correct Answer Incorrect Answer
    C 36 Correct Answer Incorrect Answer
    D 58 Correct Answer Incorrect Answer
    E 61 Correct Answer Incorrect Answer

    Solution

    Let the age of A = A, B = B and C = C According to question, => A = 5B 6 years ago, => C - 6 = 2(A - 6) After 6 years, => A + 6 = 31 => A = 25 So, B = 25/5 = 5  => C = 2(A - 6) + 6 => C = 2(25 - 6) + 6  => C = 38 + 6 = 44 Sum of the present ages of B and C = 5 + 44 = 49 years

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