The ages of A, B and C together are 64 years. B is twice as old as A and C is 4 years older than A. What is the difference between ages of B and C?
Let A’s age be x years. B’s age = 2x and C’s age = (4 + x) According to question, => x + 2x + (4 + x) = 64 => 4x = 60 => x = 15 B’s age = 2x = 30 years C’s age = 4 + x = 19 years Difference between the ages of B and C = 30 – 19 = 11 years
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
25.11 × 3.98 + 26.03 × 4.12 – 33.95 + 94.9 × 4.02 =?
320.98 + 49.99% of (261.09 + 138.98) = ?
8.992 + (5.01 × 4.98) + ? = 224.03
24.96% of 380 + ? – 169.99 = 149.99% of 80
3.98 × 29.67 ÷ 11.90 of √24.89 = ?% of 199.79
?% of 399.97 = 11.982 + 16.13 × 4.16 – 35.99
?% of [(12.96 × 40.05) + 25.08 × 18.96] = 17.96 × 22.05 + 3.05 × 66.96
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)