The ratio of the present ages of ‘A’ and ‘B’ is 5:6, respectively. Three years hence from now, the age of ‘B’ will be 21 years. If the average of present ages of ‘A’, ‘B’ and ‘C’ is 22 years, then find the present age of ‘C’.
Let the present ages of ‘A’ and ‘B’ be 5x years and 6x years, respectively Therefore, 6x + 3 = 21 Or, 6x = 18 Or, x = 3 Sum of present ages of ‘A’ and ‘B’ = 5x + 6x = 33 years Sum of present ages of ‘A’, 'B’ and ‘C’ = 22 × 3 = 66 years Therefore, present age of ‘C’ = 66 – 33 = 33 years
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