Question
A is 3 years older than B while C is 4 years younger
than B. The ratio of age of A, 6 years hence and age of B, 4 years ago is 3:2. What was age of C, 10 years ago?Solution
Let the present age of B be x years. A’s present age = (x + 3) years C’s present age = (x - 4) years According to question, => [(x + 3) + 6]/(x -4) = 3/2 => x = 30 C’s age, 10 years ago = (30 - 4) – 10 = 16 years
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