A is 3 years older than B while C is 5 years younger than B. The ratio of age of A, 6 years hence and age of B, 3 years ago is 4:3. What was age of C, 11 years ago?
Let the present age of B be x years. A’s present age = (x + 3) years C’s present age = (x - 5) years According to question, => [(x + 3) + 6]/(x - 3) = 4/3 => x = 39 C’s age, 11 years ago = (39 - 5) – 11 = 23 years
44.87% of (39.85 × ?) – 1520.88 0.51 = 1400.8
13.96% of (141.17 + 158.85) + 7.95³ - (6.88 of 9.07) = ? of (58.06 - 13.02)
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
(7.992/√?) + √16/? = 14.032/?
33.33% of 179.99 = 29.98% of 199.98 - ?
(14.56)² × √840 =?
...(3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
6.992 + (2.01 × 2.98) + ? = 175.03
1219.98 ÷ 30.48 × 15.12 = ? × 2.16