B is 4 years older than A and A is 8 years older than C. If the sum of the age of A and C is 22 years, then find the sum of the ages of all three.
Let C’s present age be x years. So, A’s present age = (x + 8) years And B’s present age = (x + 8 + 4) = (x + 12) years According to question, => x + 8 + x = 22 => 2x = 14 => x = 7 Required total sum = x + (x + 8) + (x + 12) = 3x + 20 = 41 years
44.87% of (39.85 × ?) – 1520.88 0.51 = 1400.8
13.96% of (141.17 + 158.85) + 7.95³ - (6.88 of 9.07) = ? of (58.06 - 13.02)
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
(7.992/√?) + √16/? = 14.032/?
33.33% of 179.99 = 29.98% of 199.98 - ?
(14.56)² × √840 =?
...(3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
6.992 + (2.01 × 2.98) + ? = 175.03
1219.98 ÷ 30.48 × 15.12 = ? × 2.16