Question
The ratio of the present ages of father and his son is
9:4. The product of their ages 3 years ago was 24 times of his son’s age that year. What was son’s age 2 year ago?Solution
Let present age of father and son be 9x and 4x respectively. According to question,  => (9x – 3) (4x – 3) = 24 × (4x – 3)  => (9x – 3) = 24 => 9x = 27 => x = 3 Therefore, son’s age 2 years ago = (4x – 2) = 10 years
Find the value of (1 - sin2q) X (secq + tanq) X (secq - tanq) X cosec2q
If tan θ = 4/3 and θ is an acute angle, find the value of sin θ + cos θ.

What is the value of cos75°?Â
Simplify (cos20°+sin 20°) /(cos20°-sin20°)
In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?
- Find the value of sin²50° + sin²40°.
tan 4˚ × tan 43˚ × tan 47˚ × tan 86˚ = ?
Simplify the given equation:

- In a triangle ABC, if 5∠A = 3∠B = 15∠C, then find the value of cosA + sin(C + 25 ° )