The ratio of age of A and his son is 5:1. If the difference of their ages 6 years ago is 24, then find the sum of the ages of A and his son together 11 years hence.
Let the present age of A and his son be 5x and x respectively. => (5x – 6) – (x – 6) = 24 => x = 6 then the fathers age will be = (5x + 11 = (5 × 6) + 11) = 41 yrs then the Son age will be = (x + 11) = 6 + 11 = 17 yrs Required sum = 41 + 17 = 58 yrs
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