The ratio of age of A and his son is 10:3. If the difference of their ages 8 year ago is 28, then find the sum of ages of A and his son 12 year hence.
Let the present age of Raman and his son be 10x and 3x respectively. => 10x – 3x = 28 ∴ x = 4 Required sum = 13 × 4 + 24 = 76 years
31.98% of 449.99 = ? - 194.97 + 59.98% of 124.99
(15.98% of 399.99) - 6.998 = √?
25.31% of 5199.90 + (19.9 × 17.11) + 46.021 =? + 168.98
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?
[(343) 1/3 ÷ {(12.001)2 × (1 ÷ (4.03 × 2.97) 2 )}] = ?
? = {29.7% of (97.72 × 40.04)} ÷ 3.92
45.22% of (71.9 x 5.01) + 69.97 =?
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
(168.24 ÷ 23.98) x 19.81 + ? = 176.33
