Present age of ‘A’ is 30% more than that of ‘B’. If 8 years hence from now, ‘B’ will be 9 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.3 = ‘1.3x’ years ATQ; (x + 8) + 9 = (1.3x + 8) Or, x + 17 = 1.3x + 8 Or, 9 = 0.3x Or, x = 30 So, present age of ‘B’ = 30 years And, present age of ‘A’ = 30 + 9 = 39 years Required sum = 39 + 30 = 69 years
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