Present age of ‘A’ is 40% more than that of ‘B’. If 10 years hence from now, ‘B’ will be 4 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 10) + 4 = (1.40x + 10) Or, x + 14 = 1.40x + 10 Or, 4 = 0.40x Or, x = 10 So, present age of ‘B’ = 10 years And, present age of ‘A’ = 10 + 4 = 14 years Required sum = 10 + 14 = 24 years
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