Present age of ‘A’ is 50% more than that of ‘B’. If 12 years hence from now, ‘B’ will be 7 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.50 = ‘1.50x’ years ATQ; (x + 12) + 7 = (1.50x + 12) Or, x + 19 = 1.50x + 12 Or, 7 = 0.50x Or, x = 14 So, present age of ‘B’ = 14 years And, present age of ‘A’ = 14 + 7 = 21 years Required sum = 14 + 21 = 35 years
√323.89 × (3.20) ÷ 9.02 =?
599.9 - ? + 64.9 = (5% of 300.012) × 10.032
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
14.232 + 19.98% of 629.99 = ? × 6.99
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
25.22% of (59.9 × 8.01) + 69.97 =?
13³ + 1.3² + 1.03¹ + 1.003 = ?