Present age of ‘A’ is 50% more than that of ‘B’. If 12 years hence from now, ‘B’ will be 7 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.50 = ‘1.50x’ years ATQ; (x + 12) + 7 = (1.50x + 12) Or, x + 19 = 1.50x + 12 Or, 7 = 0.50x Or, x = 14 So, present age of ‘B’ = 14 years And, present age of ‘A’ = 14 + 7 = 21 years Required sum = 14 + 21 = 35 years
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