Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 8 years hence from now will be 3 times of A's age, 2 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 8) = 3 x (3x - 2) Or, 5x + 8 = 9x - 6 Or, 4x = 14 x = 3.5 So, present age of 'A' = 3 x 3.5 = 10.5 years
More Age Questions
?% of (128.31 ÷ 15.97 × 75.011) = 419.98
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?
22.11 × 4.98 + 23.03 × 5.12 – 32.95 + 96.9 × 5.02 =?
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
(? + 6.063.03 ) ÷ 10.08 + 21.89 × 6.97 = 1979.97 ÷ 10.96
20.57 ×28.04 ÷ ? + 254 = 429.06
287.97 ÷ √323.99 = ? + 4.05-2 × 64.05
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
