New SIDBI Grade A New Batch Starts on Nov 18

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    Question

    Present ages of 'A' and 'B' are in the ratio 3:5, respectively. If B's age, 11 years hence from now will be 5 times of A's age, 18 years ago from now, then find the present age of 'A'.

    A 30.3 years Correct Answer Incorrect Answer
    B 31.3 years Correct Answer Incorrect Answer
    C 32.3 years Correct Answer Incorrect Answer
    D 34.3 years Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 11) = 5 x (3x - 18) Or, 5x + 11 = 15x - 90 Or, 10x = 101 x = 10.1 So, present age of 'A' = 3 x 10.1 = 30.3 years

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