Question
The ratio of age of ‘B’ after 6 years from now and
age of ‘C’ 4 years ago from now is 7:4, respectively. The present age of ‘C’ is 40% of the present age of ‘A’. If present age of ‘A’ is 50 years then find the present age of ‘B’.Solution
Present age of ‘C’ = 0.4 × 50 = 20 years 4 years ago from now, age of ‘C’ = 20 – 4 = 16 years 6 years hence from now, age of ‘B’ = 16 × (7/4) = 28 years Present age of ‘B’ = 28 – 6 = 22 years
I. x²= 961
II. y= √961
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I.√(3x-17)+ x=15
II. y + 135/y=24
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 375 = 0
Equation 2: y² - 36y + 324 = 0
What is the speed of the stream if a ship takes 15 hours to travel 240 km in calm waters, given that the ratio of its speed against the current to its s...
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
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