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According to the question, Present ages of (A + B) = 10 × 2 = 20…. (1) Than, the Present ages of (A + C) = 6 × 2 = 12…. (2) Than, the Present ages of (B + C) = 12 × 2 = 24….. (3) Therefore From equations (1), (2) and (3), we get Present ages of (A + B + C) = (20 + 12 + 24)/2 = 28 years Therefore From equation (3)we will get the, present age of ‘A’ = 28 – 24 = 4 years
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Quiescent centre is found in plants at
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Insects are studied in .......................................?
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