Question
The present average age of βXβ and βYβ is 16
years, present average age of βXβ and βZβ is 56 years and present average age of βYβ and βZβ is 22 years. Find the present age of βXβ.Solution
According to the question, Present ages of (X + Y) = 16 Γ 2 = 32β¦. (1) Than, the Present ages of (X + Z) = 56 Γ 2 = 112β¦. (2) Than, the Present ages of (Y + Z) = 22 Γ 2 = 44β¦.. (3) Therefore From equations (1), (2) and (3), we get Present ages of (X + Y + Z) = (32 + 112+ 44)/2 = 94 years Therefore From equation (3)we will get the, present age of βXβ = 94 β 44 = 50 years
More Age Questions
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) β (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? Γ· β 16
? = 20% of 1200 + 256
21% of 400 β 150 = ? β 77
172Β - 92Β + 121 - 74 = ?
24% of 150% of 500 + 140 = ? Γ 8Β
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 Γ 250) β 200
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