Mukesh's age is four times his son's age If, after 8 years, Mukesh will be four times his son's age, how many times his son's age will Mukesh be after another 8 years?
ATQ, Let son’s age be x and Mukesh’s age be 4x. Mukesh’s age is 4 times more aged than his son, therefore Mukesh’s present age = x + 4x = 5x After 8 years, Mukesh’s age is 4 times more than his son age. (5x + 8) = 4(x + 8) 5x - 4x = 32 - 8 x = 24 After 8 years it was (5x + 8), then after further 8 years, Mukesh’s age = (5x + 16) and Son age = x + 16 (5x + 16)/x + 16 =? Substitute the value of x, we get = 5(24) + 16/24 + 16 = (120 + 16)/40 = 17/5 After further 8 years, Suresh will be 17/5 times of son’s age.
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