Sum of the present ages of Gaurav and Shubham is 100. Age of Gaurav four years ago was twice the age of Shubham six years ago. Find the square root of age of Gaurav?
Let the present age of Gaurav be G and that of Shubham be S. G + S = 100; (G - 4) =2(S - 6) => G + 8 = 2S => G + 8 = 2(100-G) => 3G = 192 => G = 64 Square root of G = √ 64 = 8
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