The ratio of age of A and B after 8 years is 4:5 respectively. The ratio of age of A and C 6 years ago is 3:4 respectively. If the present average age of A and C is 30 years, then find the present age of C.
Let the age of A and B after 8 years be 4x years. and 5x years respectively. And the present age of C is ‘y’ years. So, (4x – 14)/ (y – 6) = 3/4 16x – 56 = 3y – 18 16x – 3y = 38……………. (1) And 4x – 8 + y = 60 y = 68 – 4x…………………. (2) From equations (1) and (2), we get. 16x – 204 + 12x = 38 28x = 242 x = 8.6 Present age of C = 62 -(4 ×8.6) = 27.6years
√323.89 × (3.20) ÷ 9.02 =?
599.9 - ? + 64.9 = (5% of 300.012) × 10.032
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
14.232 + 19.98% of 629.99 = ? × 6.99
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
25.22% of (59.9 × 8.01) + 69.97 =?
13³ + 1.3² + 1.03¹ + 1.003 = ?
