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Let the age of A and C 10 years from now we 3X years and 5X year respectively. So age of B 10 years from now = (3X+5X)/2 = 4x years. As per question (3x-10+4x-10+5x-10)/3 = 1.2*(3x-10+4x-10)/2 24x-60 = 3.6*(7x-20) 24x-60 = 25.2x-72 1.2x=12 X=10 Sum of present age of B and C = (4*10-10) +(5*10-10) = 70 years.
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I. 8x2- 2x – 15 = 0
II. 12y2- 17y – 40 = 0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. 3x² - 22 x + 40 = 0
II. 4y² + 22y + 24 = 0
I. 2b2- 37b + 143 = 0
II. 2a2+ 15a - 143 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I. x2 - x - 56 = 0
II. y2 - 20y + 96 = 0