The average ages of A, B and C is 20% more than the average ages of A and B. 10years hence from now, the ratio of the ages of A and C will be 3:5, respectively and age of B will be the mean of their ages at the time. Find the sum of present ages of B and C.
Let the age of A and C 10 years from now we 3X years and 5X year respectively. So age of B 10 years from now = (3X+5X)/2 = 4x years. As per question (3x-10+4x-10+5x-10)/3 = 1.2*(3x-10+4x-10)/2 24x-60 = 3.6*(7x-20) 24x-60 = 25.2x-72 1.2x=12 X=10 Sum of present age of B and C = (4*10-10) +(5*10-10) = 70 years.
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