Four years ago, the age of the mother was 12 times the age of her daughter. Two years hence, the mother's age will be 4 times the daughter's age. After how many years will the mother's age be 3 times that of her daughter?
Let the present age of the daughter be x years. Four years ago, the age of the daughter = (x - 4) years Four years ago, the age of the mother = 12 × (x - 4) = (12x - 48) years Two years hence, Age of the daughter = (x - 4) + 4 + 2 = (x + 2) years Age of the mother = (12x - 48) + 4 + 2 = (12x - 42) years According to the question, (x + 2) × 4 = (12x - 42) =4x + 8 = 12x - 42 = 12x – 4x = 42 + 8 8x =50 x = 6.25 Now, the present age of the mother = (12x - 48) + 4 = 12x - 44 = 12 × 6.25 - 44 = 31 Let after y years the age of the mother will be three times that of her daughter. According to the question, (6.25 + y) × 3 = (31 + y) = 18.75 + 3y = 31 + y = 2y = 31 – 18.75 y = 12.25/2 y = 6.125=6(1/8) years. After 6(1/8) years, the mother's age will be 3 times that of her daughter.
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs...
I. 2p2 + 25p – 13 = 0
II. 2q2 – 19q = 2q + 23
I. 4x2+ 25x + 36 =0
II. 2y2+ 5y + 3 = 0
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. √(17x) + √51 = 0
II. √(4y) + 3 = 0