10 years ago, the ratio of the ages of Maya and Neil was 4:3. The present age of Jake is 10 years more than one-fourth of Neil’s present age. Find the present age of Jake, if Maya’s age in 6 years will be 40 years.
Maya and Neil's ages 10 years ago = 4x and 3x Present ages = 4x + 10, 3x + 10 Maya's present age = 40 – 6 = 34 years → 4x = 34 – 10 = 24 → x = 6 Neil's present age = 3(6) + 10 = 28 Jake's present age = (1/4) * 28 + 10 = 17 years
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