Start learning 50% faster. Sign in now
ATQ, Let, the present ages of 'Amit' and 'Bishnu' be '20a' years and '25a' years, respectively. So, present age of 'Chintu' = 1.4 × 20a = '28a' years ATQ, 28a + 25a = 106 So, a = (106/53) = 2 So, the present age of 'Amit' = 20a = 20 × 2 = 40 years
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
If sin3A = cos(5A-30°), then what is the value of A? Given that 3A is an acute angle.
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: