The ratio of the present age of 'E' to that of 'F' is 2:3. If six years hence, the ratio of their ages will become 3:4, find the sum of their ages, five years ago from now.
Let the present ages of 'E' and 'F' be '2z' years and '3z' years, respectively. ATQ, (2z+6)/(3z+6) = 3/4 Or, 4×(2z+6) = 3×(3z+6) Or, 8z+24 = 9z+18 Or, 9z−8z = 24−18 So, z = 6 Present age of 'E' = 2z = 2 × 6 = 12 years Present age of 'F' = 3z = 3 × 6 = 18 years Required sum = (12 - 5) + (18 - 5) = 7 + 13 = 20 years
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