The ratio of ages of A, B and C is 2 : 4 : 5 and sum of their ages is 77. Find the ratio of A's age to B's age ten years hence.
Let the ratio of ages of A, B, and C is 2x, 4x, and 5x respectively. ATQ, 2x + 4x + 5x = 77 11x = 77 x = 77/11 x = 7 10 years hence age of A = 2 x 7 + 10 = 14 + 10 = 24 10 years hence age of B = 4 × 7 + 10 = 28 + 10 = 38 The ratio of ages of A to B 10 years = 24:38 = 12:19
40% of 220 × 15 ÷ 20 = ?
[5 X {(52 X 5) - 10} + 50 of 20] = ?
315 ÷ 9 + 23 × 3+ 22 = ?× √441
375% of 320 - 80% of 40 ÷ √256 = ?
(112 × 4) ÷ 16 + 484 = (?)3
25% of 440 + 88 X (1/2)2 - 28 = 8 X ?
(43/10) + (4.2/1.2) - (2.7/3) = (?/4) + (2.7/6.0)
125 ÷ 5 + 14 × 4 = ? + 72 ÷ 4 – 35
18 + 28÷ 4 - 14 = ? - 35
...√529 + √64 + 92 = ?
