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    Question

    The present age of a father is 5 times the age of his

    son. In 6 years, the father's age will be 4 times the age of his son. How many years ago was the father's age 7 times the son's age?
    A 6 years Correct Answer Incorrect Answer
    B 10 years Correct Answer Incorrect Answer
    C 12 years Correct Answer Incorrect Answer
    D 14 years Correct Answer Incorrect Answer

    Solution

    Let the present age of the son be x years. Then the father's age is 5x years. In 6 years, the father's age will be 5x + 6 and the son's age will be x + 6. Given: 5x + 6 = 4(x + 6). 5x + 6 = 4x + 24. x = 18 years. So, the father's current age is 5 * 18 = 90 years. Let y years ago, the father's age was 7 times the son's age. 90 - y = 7(18 - y) 90 - y = 126 - 7y 6y = 36 → y = 6 years.

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