Question
Twelve years ago, the age ratio between 'A' and 'B' was
5:4. In five years, their average age is expected to be 44 years. Determine 'A’s age eight years ago.Solution
12 years ago from now, let ages of ‘A’ and ‘B’ be ‘5y’ years and ‘4y’ years respectively. ATQ, (5y + 17) + (4y + 17) = 2 × 44 Or, 9y + 34 = 88 Or, 9y = 54 Or, y = 6 So, present ages of ‘A’ = (5y + 12) = (30 + 12) = 42 years Age of ‘A’ 8 years ago from now = (42 – 8) = 34 years.
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
19.86% of 145.12 1/2 × 65.12 = ? × 2.12
(4.89)2 + √144.35 - √121.25 = ?
766/51 ÷ 387/42 × 121/13 = ?
(11.75)2 - 49.99% of 120 - ? = (8.23)2
59.68% of √400 × 123.95 = ?
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
20.11 × 6.98 + 21.03 × 6.12 – 37.95 + 92.9 × 5.02 =?
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