Question
A father is three times as old as his son. After 5
years, the father’s age will be twice that of his son. What are their current ages?Solution
Let the son's age = x. Father's age = 3x. After 5 years, (3x + 5) = 2(x + 5). Solving: 3x + 5 = 2x + 10 x = 5 Son’s age = 5 × 3 = 15 years. Correct answer: a) Father: 45, Son: 15
Statements: B ≥ U > P = E ≥ X; X > K > N ≥ J
Conclusions: I. N < P   II. J ≤ X
Statements:
P > Q < R; T ≤ U ≤ Q > S; V ≤ W < T
Conclusions:
I). Â P > V
II). Â T = S
III). Â R > V
...Statement: M < N; O ≥ P; O ≥ L; P > N ≥ Q
Conclusion:
I. N > L
II. L > Q
Statements: G > E < F; E = D > C; C = B < A
Conclusion:
I. B < F
II. G > A
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statements: J @ K, K $ L, L & M, M % N
Conclusions: I. K @ MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. N & J
...Statements: Â S * K, T $ K, K @ B
Conclusions:Â Â Â Â Â a) S $ BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â b) S @ B
...Statements: M $ K; K & N, N % R, R @ W
Conclusions:Â Â Â Â Â
I. W & KÂ Â Â Â Â Â Â Â Â Â Â Â Â Â
II. K & W         �...
Statements: J ≥ K ≥ A = M, K ≥ O > W ≥ X
Conclusion:
I. J ≥ X
II. J > X
Statements:
S < B < U ≤ Q; P > T ≥ F = U < I > E
Conclusion:
I. T > S
II. B ≤ I