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Let the ages of 'A' and 'B' six year ago from now be '3y' and '5y' years respectively. So, present ages of 'A' and 'B' will be (3y + 6) and (5y + 6) years respectively. ATQ: (3y + 6 + 8) :(5y + 6 + 8) = 5:6 Or, (3y + 14) :(5y + 14) = 5:6 Or, 6 X (3y + 14) = 5 X (5y + 14) Or, 18y + 84 = 25y + 70 Or, 7y = 14 So, 'y' = 2 So, present age of 'B' = 5 X 2 + 6 = 16 years So, age of 'B' 2 years hence from now = 16 + 2 = 18 years Let the ages of 'A' and 'B' six year ago from now be '3y' and '5y' years respectively. So, present ages of 'A' and 'B' will be (3y + 6) and (5y + 6) years respectively. ATQ: (3y + 6 + 8) :(5y + 6 + 8) = 5:6 Or, (3y + 14) :(5y + 14) = 5:6 Or, 6 X (3y + 14) = 5 X (5y + 14) Or, 18y + 84 = 25y + 70 Or, 7y = 14 So, 'y' = 2 So, present age of 'B' = 5 X 2 + 6 = 16 years So, age of 'B' 2 years hence from now = 16 + 2 = 18 years
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If x + y + z = 6, and x3 + y3 + z3 = 36, xyz = 6 then find (xy +yz + zx)?
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
If (Ax + By - Cz) 2 = 4x 2 + 3y 2 + 2z 2 + 4√3xy - 2√6yz - 4√2xz, then find the value of A