If (x24 + 1)/x12 = 7, then the value of (x72 + 1)/x36 is
(x24 + 1)/x12 = 7 ⇒ x24/x12 + 1/x12 = 7 ⇒ x12 + 1/x12 = 7 ∴ (x72 + 1)/x36 = x72/x36 + 1/x36 = x36 + 1/x36 = (x12 + 1/x12 )3 – 3 × x12 × 1/x12 (x12 + 1/x12) ∵ (a + b)³ = a³ + b³ + 3ab (a + b) = 7³ - 3 × 7 = 343 – 21 = 322
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
